16t^2+64t-60=60

Solution for 16t^2+64t-60=60 equation:

16t^2+64t-60=60

We move all terms to the left:

16t^2+64t-60-(60)=0

We add all the numbers together, and all the variables

16t^2+64t-120=0

a = 16; b = 64; c = -120;
Δ = b2-4ac
Δ = 642-4·16·(-120)
Δ = 11776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11776}=\sqrt{256*46}=\sqrt{256}*\sqrt{46}=16\sqrt{46}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-16\sqrt{46}}{2*16}=\frac{-64-16\sqrt{46}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+16\sqrt{46}}{2*16}=\frac{-64+16\sqrt{46}}{32}
$